Question:


Shown in the figure is rigid and uniform one meter long rod \(AB\) held in horizontal position by two strings tied to its ends and attached to the ceiling. The rod is of mass \(m\) and has another weight of mass \(2m\) hung at a distance of 75 cm from \(A\). The tension in the string at \(A\) is :

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Take torques about end \(B\) (rod in rotational equilibrium) and include the rod weight acting at its midpoint.
Updated On: Nov 5, 2026
  • 0.5 mg
  • 2 mg
  • 0.75 mg
  • 1 mg
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The Correct Option is D

Solution and Explanation

Let \(T_A, T_B\) be the string tensions; the rod weight \(mg\) acts at 50 cm from \(A\), the hanging weight \(2mg\) at 75 cm from \(A\) (25 cm from \(B\)).
Torque about \(B\) = 0: \(T_A\times 1 = mg\times 0.5 + 2mg\times 0.25\).
\(T_A = 0.5\,mg + 0.5\,mg = mg\).
(Check: \(T_B = 3mg - mg = 2mg\).)
Answer: (4) 1 mg
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