Same current is flowing in two AC circuits. First contains only inductance and second contains only capacitance. If frequency of AC is increased for both, the current will
Show Hint
Inductive reactance rises with frequency while capacitive reactance falls with frequency.
Step 1: Understanding the Concept
Inductive reactance is \(X_L=2\pi fL\). Capacitive reactance is \(X_C=\dfrac{1}{2\pi fC}\).
Step 2: Effect of raising frequency
\(X_L\) increases, so the current \(I=\dfrac{V}{X_L}\) decreases in the first circuit.
\(X_C\) decreases, so the current \(I=\dfrac{V}{X_C}\) increases in the second circuit.
Step 3: Compare the options
This is option (D).
Final Answer:
The current decreases in the inductive circuit and increases in the capacitive circuit.
\[ \boxed{\text{(D) }\text{decrease in first circuit and increase in second}} \]