Question

Resistance of 0.1 M KCl solution in a conductivity cell is 300 ohm and conductivity is 0.013 S cm\(^{-1}\). What is the cell constant?

• A. 4.5 cm\(^{-1}\)
• B. 3.0 cm\(^{-1}\)
• C. 1.5 cm\(^{-1}\)
• D. 3.9 cm\(^{-1}\)

Hint:

The cell constant is calculated by dividing the conductivity by the resistance in a conductivity cell.

Answer 1

The Correct Option is D

Step 1: Understanding the relation.
The cell constant \( K \) can be calculated using the formula: \[ K = \frac{\kappa}{R} \] Where \( \kappa \) is the conductivity and \( R \) is the resistance of the solution.
Step 2: Applying the values.
We are given the conductivity \( \kappa = 0.013 \, \text{S cm}^{-1} \) and resistance \( R = 300 \, \Omega \). Thus, the cell constant is: \[ K = \frac{0.013}{300} = 3.9 \, \text{cm}^{-1} \] Step 3: Conclusion.
The correct answer is (D) 3.9 cm\(^{-1}\).