Question:
Relative acidity of the following is in the order
Relative acidity of the following is in the order
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Acidity order: Carboxylic acids>Carbonic acid>Phenols>Water>Alcohols.
Updated On: May 2, 2026
- RCOOH>H\(_2\)CO\(_3\)>C\(_6\)H\(_5\)OH>H\(_2\)O>ROH
- RCOOH>ROH>H\(_2\)CO\(_3\)>C\(_6\)H\(_5\)OH>H\(_2\)O
- ROH>RCOOH>H\(_2\)CO\(_3\)>C\(_6\)H\(_5\)OH>H\(_2\)O
- RCOOH>C\(_6\)H\(_5\)OH>ROH>H\(_2\)CO\(_3\)>H\(_2\)O
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept:
Acidity depends on the stability of the conjugate base formed after losing a proton.
Step 2: Detailed Explanation:
\begin{itemize} \item RCOOH (Carboxylic acids): Strongest among these due to resonance stabilization of carboxylate ion. pKa ≈ 4-5. \item H\(_2\)CO\(_3\) (Carbonic acid): Weak acid, pKa ≈ 6.4. \item C\(_6\)H\(_5\)OH (Phenol): Weak acid, pKa ≈ 10. \item H\(_2\)O (Water): Very weak acid, pKa ≈ 15.7. \item ROH (Alcohols): Very weak acid, pKa ≈ 16-18. \end{itemize}
Step 3: Final Answer:
The correct order is RCOOH>H\(_2\)CO\(_3\)>C\(_6\)H\(_5\)OH>H\(_2\)O>ROH, option (A).
Acidity depends on the stability of the conjugate base formed after losing a proton.
Step 2: Detailed Explanation:
\begin{itemize} \item RCOOH (Carboxylic acids): Strongest among these due to resonance stabilization of carboxylate ion. pKa ≈ 4-5. \item H\(_2\)CO\(_3\) (Carbonic acid): Weak acid, pKa ≈ 6.4. \item C\(_6\)H\(_5\)OH (Phenol): Weak acid, pKa ≈ 10. \item H\(_2\)O (Water): Very weak acid, pKa ≈ 15.7. \item ROH (Alcohols): Very weak acid, pKa ≈ 16-18. \end{itemize}
Step 3: Final Answer:
The correct order is RCOOH>H\(_2\)CO\(_3\)>C\(_6\)H\(_5\)OH>H\(_2\)O>ROH, option (A).
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