Rate of radiation by a black body is $R$ at temperature $T$. Another body has the same area but emissivity is $0.2$ and temperature is $3T$. Its rate of radiation is
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Radiated power varies as the fourth power of absolute temperature.
Step 1: Apply Stefan–Boltzmann law.
The power radiated is given by:
\[
P = e \sigma A T^4
\]
Step 2: Radiation from black body.
For a black body, emissivity $e = 1$, hence:
\[
R = \sigma A T^4
\]
Step 3: Radiation from second body.
\[
P' = 0.2 \times \sigma A (3T)^4
\]
Step 4: Simplification.
\[
P' = 0.2 \times 81 \times \sigma A T^4 = 16.2 \sigma A T^4
\]
Step 5: Final comparison.
\[
P' = 16.2R
\]