Rate law for the reaction, \( NO_{2(g)} + CO_{g} \rightarrow NO_{(g)} + CO_{2(g)} \) is as \( R = k[NO_{2}]^2 \). What is the order of reaction w.r.t. CO?
Show Hint
If a reactant is missing from the rate law expression, the reaction is zero-order with respect to that reactant.
Step 1: Concept
The order of reaction with respect to a reactant is the exponent to which its concentration term is raised in the rate law.
Step 2: Analysis
The given rate law is $R = k[NO_2]^2$.
Step 3: Comparison
Since the concentration of CO does not appear in the rate law, it is mathematically $[CO]^0$.
Step 4: Conclusion
The order with respect to CO is 0.
Final Answer:(A)