Step 1: Understanding the Question:
We are given a discrete probability distribution table outlining various potential maintenance costs (random variable $x_i$) alongside their historical probabilities of occurrence ($p_i$). We need to calculate the mathematical expected value ($E(x)$) of this distribution.
Step 2: Key Formula or Approach:
The expected value of a discrete random variable is the weighted average of all possible values, calculated by taking the sum of the products of each value and its corresponding probability:
$$ E(x) = \sum p_i x_i $$
Step 3: Detailed Explanation:
Let's list the paired value and probability products systematically from the distribution context:
• For expense 0: $0 \times 0.35 = 0$
• For expense 500: $500 \times 0.25 = 125$
• For expense 1000: $1000 \times 0.15 = 150$
• For expense 1500: $1500 \times 0.10 = 150$
• For expense 2000: $2000 \times 0.08 = 160$
• For expense 2500: $2500 \times 0.05 = 125$
• For expense 3000: $3000 \times 0.02 = 60$
Now, sum these individual expected component contributions together to find the total:
$$ E(x) = 0 + 125 + 150 + 150 + 160 + 125 + 60 $$
$$ E(x) = 275 + 150 + 160 + 125 + 60 $$
$$ E(x) = 425 + 160 + 125 + 60 $$
$$ E(x) = 585 + 125 + 60 = 710 + 60 = 770 $$
The statistically expected long-term maintenance expense is Rs. 770.
Step 4: Final Answer:
The expected value of the maintenance cost is Rs. 770, which corresponds to option (B).