Step 1: Understanding the Question:
We need to test the given options against a set of constraints regarding who can and cannot be sent together in a 5-member team (consisting of 2 managers and 3 faculty members).
Step 2: Detailed Explanation:
Let us list the negative selection constraints:
1. Constraint (K): 'a' and 'c' cannot be together.
2. Constraint (L): 'c' and 'e' cannot be together.
3. Constraint (M): 'd' and 'g' cannot be together.
4. Constraint (N): 'd' and 'f' cannot be together.
Let us evaluate each option against these constraints:
- Option (A): `a -> b -> d -> e -> h`
- Contains 'a' and 'b' (Constraint K satisfied).
- Contains 'd', 'e', 'h' (Constraints L, M, and N satisfied since 'c', 'g', and 'f' are not present). This is a possible team.
- Option (B): `a -> b -> f -> g -> h`
- Contains 'a' and 'b' (Constraint K satisfied).
- Contains 'f', 'g', 'h' (Constraints L, M, and N satisfied since 'c' and 'd' are not present). This is a possible team.
- Option (C): `a -> b -> e -> g -> h`
- Contains 'a' and 'b' (Constraint K satisfied).
- Contains 'e', 'g', 'h' (Constraints L, M, and N satisfied since 'c' and 'd' are not present). This is a possible team.
- Option (D): `a -> b -> d -> g -> h`
- Contains 'd' and 'g' together in the team.
- This directly violates Constraint (M): "If 'd' is sent, then 'g' cannot be sent, and vice versa."
Therefore, Option (D) cannot be a possible working unit.
Step 3: Final Answer:
(D) a \(\rightarrow\) b \(\rightarrow\) d \(\rightarrow\) g \(\rightarrow\) h