Question:
Propene on hydroboration followed by oxidation with alkaline peroxide forms.
Propene on hydroboration followed by oxidation with alkaline peroxide forms.
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Hydroboration-oxidation adds water in an anti-Markovnikov manner, giving the primary alcohol.
Updated On: Nov 13, 2026
- Tri-n-propylborane
- Tri iso propylborane
- Propan-1-ol
- Propan-2-ol
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Hydroboration-oxidation converts an alkene to an alcohol by anti-Markovnikov addition of water.
Step 2: Reaction
\(3\,\text{CH}_3\text{CH}=\text{CH}_2 + \text{BH}_3 \rightarrow (\text{CH}_3\text{CH}_2\text{CH}_2)_3\text{B}\)
\((\text{CH}_3\text{CH}_2\text{CH}_2)_3\text{B} \xrightarrow{\text{H}_2\text{O}_2,\ \text{OH}^{-}} 3\,\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}\)
Step 3: Compare the options
The trialkylborane is an intermediate, not the final product. The final product is propan-1-ol.
Final Answer:
The final product is propan-1-ol. \[ \boxed{\text{(C) }\text{Propan-1-ol}} \]
Hydroboration-oxidation converts an alkene to an alcohol by anti-Markovnikov addition of water.
Step 2: Reaction
\(3\,\text{CH}_3\text{CH}=\text{CH}_2 + \text{BH}_3 \rightarrow (\text{CH}_3\text{CH}_2\text{CH}_2)_3\text{B}\)
\((\text{CH}_3\text{CH}_2\text{CH}_2)_3\text{B} \xrightarrow{\text{H}_2\text{O}_2,\ \text{OH}^{-}} 3\,\text{CH}_3\text{CH}_2\text{CH}_2\text{OH}\)
Step 3: Compare the options
The trialkylborane is an intermediate, not the final product. The final product is propan-1-ol.
Final Answer:
The final product is propan-1-ol. \[ \boxed{\text{(C) }\text{Propan-1-ol}} \]
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