Question:
Probability of getting a head in a fair coin toss:
Probability of getting a head in a fair coin toss:
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The sum of probabilities of all elementary events in an experiment is always 1. Here, $P(H) + P(T) = 0.5 + 0.5 = 1$.
Updated On: Apr 2, 2026
- 0
- 1
- 1/2
- 2
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Probability is defined as the number of favorable outcomes divided by the total number of possible outcomes in the sample space.
Step 2: Detailed Explanation:
For a fair coin, the sample space $S = \{H, T\}$. Total number of outcomes $n(S) = 2$. Event $E$ of getting a head $= \{H\}$. Number of favorable outcomes $n(E) = 1$. $P(E) = \frac{n(E)}{n(S)} = \frac{1}{2}$.
Step 3: Final Answer:
The probability is 1/2.
Probability is defined as the number of favorable outcomes divided by the total number of possible outcomes in the sample space.
Step 2: Detailed Explanation:
For a fair coin, the sample space $S = \{H, T\}$. Total number of outcomes $n(S) = 2$. Event $E$ of getting a head $= \{H\}$. Number of favorable outcomes $n(E) = 1$. $P(E) = \frac{n(E)}{n(S)} = \frac{1}{2}$.
Step 3: Final Answer:
The probability is 1/2.
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