Question:
Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is :
Pressure inside two soap bubbles are 1.01 and 1.02 atmosphere, respectively. The ratio of their volumes is :
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Excess pressure in a soap bubble is \(4T/r\); the excess over 1 atm is 0.01 and 0.02 atm.
Updated On: Nov 5, 2026
- 4 : 1
- 8 : 1
- 2 : 1
- 0.8 : 1
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The Correct Option is B
Solution and Explanation
Atmospheric pressure is 1 atm, so excess pressures are \(\Delta P_1 = 0.01\) atm and \(\Delta P_2 = 0.02\) atm.
For a soap bubble \(\Delta P = 4T/r\), so \(r\propto 1/\Delta P\): \(r_1/r_2 = \Delta P_2/\Delta P_1 = 2\).
Volume \(V\propto r^3\): \(V_1/V_2 = 2^3 = 8\).
Ratio of volumes \(= 8:1\).
Answer: (2) 8 : 1
For a soap bubble \(\Delta P = 4T/r\), so \(r\propto 1/\Delta P\): \(r_1/r_2 = \Delta P_2/\Delta P_1 = 2\).
Volume \(V\propto r^3\): \(V_1/V_2 = 2^3 = 8\).
Ratio of volumes \(= 8:1\).
Answer: (2) 8 : 1
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