Concept:
Alcohols contain an \(-OH\) group, where the hydrogen atom is slightly acidic.
When alcohol reacts with an active metal such as
sodium, the metal replaces the hydrogen of the hydroxyl group.
This reaction forms a
sodium alkoxide and releases
hydrogen gas.
Step 1: {Write the general reaction.}
For a general alcohol \(ROH\):
\[
2ROH + 2Na \rightarrow 2RONa + H_2
\]
where
- \(RONa\) = sodium alkoxide
- \(H_2\) = hydrogen gas
Step 2: {Example reaction.}
For ethanol:
\[
2C_2H_5OH + 2Na \rightarrow 2C_2H_5ONa + H_2
\]
Thus, ethanol forms
sodium ethoxide and hydrogen gas.
Step 3: {Identify the products.}
Therefore, the reaction between alcohol and sodium produces
\[
\text{Sodium alkoxide} + H_2
\]