Question

Predict the oxidation number of 'C' in \(\text{K}_{2}\text{C}_{2}\text{O}_{4}\) and in \(\text{CH}_{2}\text{Cl}_{2}\).

• A. \(+3\) and \(+2\)
• B. \(+3\) and \(0\)
• C. \(-3\) and \(+2\)
• D. \(+3\) and \(-2\)

Hint:

Use the sum of oxidation numbers equal to zero, with K as +1, O as -2, H as +1 and Cl as -1.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept
In a neutral compound the oxidation numbers of all atoms add up to zero.

Step 2: In \(\text{K}_2\text{C}_2\text{O}_4\)
Let C be \(x\): \(2(+1)+2x+4(-2)=0\), so \(2x=6\) and \(x=+3\).

Step 3: In \(\text{CH}_2\text{Cl}_2\)
Let C be \(y\): \(y+2(+1)+2(-1)=0\), so \(y=0\).

Final Answer:
Carbon is +3 in potassium oxalate and 0 in dichloromethane. \[ \boxed{\text{(B) }+3\text{ and }0} \]