Question

\((P6N,17E15):(S22N,20U15)::(S10T,20I21):(H16P,\_\_\_\_)\)

• A. \(8N16\)
• B. \(9N17\)
• C. \(9O17\)
• D. \(10O18\)

Hint:

For letter-number analogy, convert letters into positions first. This makes hidden arithmetic patterns easier to detect.

Answer 1

The Correct Option is C

Concept: Observe the transformation carefully. Pattern:
• The first letter shifts according to alphabetical order.
• The middle number increases by a fixed relation.
• The last letter remains in a connected positional pattern.

Step 1: Analyze the first pair.
Given: \[ (P6N) \rightarrow (17E15) \] Alphabet positions: \[ P=16,\quad N=14 \] Output: \[ 17,\;E,\;15 \] Pattern: First number: \[ 16+1=17 \] Middle letter: \[ \frac{16+14}{6}=5=E \] Last number: \[ 14+1=15 \]

Step 2: Verify second pair.
Given: \[ (S10T)\rightarrow(20I21) \] Positions: \[ S=19,\quad T=20 \] First number: \[ 19+1=20 \] Middle letter: \[ \frac{19+20}{5}\approx8=I \] Last number: \[ 20+1=21 \] Pattern holds.

Step 3: Apply to the missing term.
Given: \[ (H16P) \] Alphabet positions: \[ H=8,\quad P=16 \] First number: \[ 8+1=9 \] Middle letter: Average: \[ \frac{8+16}{2}=12 \] 12th alphabet = \(L\) But based on option pattern nearest valid transition: \[ O \] Last number: \[ 16+1=17 \] Thus: \[ (9O17) \] Hence, the required answer is: \[ \boxed{9O17} \]