Question

\[ \frac{15}{\text{CE}} : \underline{\hspace{2cm}} \; :: \; \frac{77}{\text{GK}} : \frac{143}{\text{KM}} \] 

• A. \(\frac{35}{DE}\)
• B. \(\frac{35}{EF}\)
• C. \(\frac{35}{DF}\)
• D. \(\frac{35}{EG}\)

Hint:

In letter-number analogies, immediately convert letters into their alphabetical positions and look for multiplication, addition, or difference patterns.

Answer 1

The Correct Option is B

Concept: The numerator is obtained as the product of the alphabetical positions of the two letters in the denominator.

Step 1: Verify the given example. For \[ GK \] Alphabetical positions: \[ G=7,\qquad K=11. \] Their product is \[ 7\times11=77. \] Thus \[ \frac{77}{GK}. \] Similarly, \[ K=11,\qquad M=13. \] Therefore \[ 11\times13=143. \] Hence \[ \frac{143}{KM}. \] The pattern is confirmed.

Step 2: Apply the same rule to the first fraction. For \[ CE, \] \[ C=3,\qquad E=5. \] Thus \[ 3\times5=15. \] Now the next pair should move forward by one letter each: \[ EF. \] Positions: \[ E=5,\qquad F=7. \] Therefore \[ 5\times7=35. \] Hence the required term is \[ \boxed{\frac{35}{EF}}. \]