Step 1: Understanding the Question:
We are given scheduling details for seven friends (P, Q, R, S, T, V, W) leaving for seven different cities on seven different days of the week (Monday to Sunday). We need to construct the correct schedule sequence.
Step 2: Detailed Explanation:
Let us list the days from Monday to Sunday and fill in the clues:
- Clue (K): R left for Jaipur on Monday. On Sunday, someone left for Bangalore.
- Clue (M): S left for Kolkata on Friday.
Currently, our schedule looks like:
- Monday: R (Jaipur)
- Tuesday: [Open]
- Wednesday: [Open]
- Thursday: [Open]
- Friday: S (Kolkata)
- Saturday: [Open]
- Sunday: [Open] (Bangalore)
- Clue (L): "T left the next day of P who left for Chandigarh and on the previous day of W."
This indicates that P, T, and W left on three consecutive days in that order (P \(\rightarrow\) T \(\rightarrow\) W). Additionally, we know P went to Chandigarh.
The only three consecutive open days in our schedule are Tuesday, Wednesday, and Thursday. Thus:
- Tuesday: P (Chandigarh)
- Wednesday: T
- Thursday: W (and according to Clue N, W left for Delhi)
- Clue (N): "Q did not leave for either Hyderabad or Bangalore."
This leaves Saturday and Sunday to be filled by Q and V. Since Q cannot go to Bangalore, Q cannot leave on Sunday.
Therefore, Q must leave on Saturday, and V must leave on Sunday (and go to Bangalore).
This fully determines the sequence of friends from Monday to Sunday:
\[
\text{R (Mon)} \rightarrow \text{P (Tue)} \rightarrow \text{T (Wed)} \rightarrow \text{W (Thu)} \rightarrow \text{S (Fri)} \rightarrow \text{Q (Sat)} \rightarrow \text{V (Sun)}
\]
This corresponds to Option (A).
Step 3: Final Answer:
(A) R \(\rightarrow\) P \(\rightarrow\) T \(\rightarrow\) W \(\rightarrow\) S \(\rightarrow\) Q \(\rightarrow\) V