Step 1: Use volume conservation.
Let radius of each small drop be \( r \).
Total volume of 1000 drops
\[
1000 \times \frac{4}{3}\pi r^3 = \frac{4}{3}\pi R^3
\]
\[
\Rightarrow R^3 = 1000 r^3 \Rightarrow R = 10r
\] Step 2: Write surface energy relation.
Surface energy is proportional to surface area.
Initial surface energy:
\[
E_i \propto 1000 \times 4\pi r^2
\]
Final surface energy:
\[
E_f \propto 4\pi R^2 = 4\pi (10r)^2 = 400\pi r^2
\] Step 3: Find ratio.
\[
\frac{E_f}{E_i} = \frac{400\pi r^2}{1000 \times 4\pi r^2} = \frac{1}{10}
\] Step 4: Conclusion.
The ratio of final surface energy to initial surface energy is \( 1 : 10 \).