Question:
One of the foci of the hyperbola \( \frac{x^2}{9} - \frac{y^2}{16} = 1 \) is
One of the foci of the hyperbola \( \frac{x^2}{9} - \frac{y^2}{16} = 1 \) is
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Hyperbola uses \(c^2 = a^2 + b^2\), unlike ellipse.
Updated On: Apr 30, 2026
- \((3,0)\)
- \((4,0)\)
- \((5,0)\)
- \((9,0)\)
- \((2,0)\)
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The Correct Option is C
Solution and Explanation
Concept:
For hyperbola:
\[
c^2 = a^2 + b^2
\]
Step 1: Identify values. \[ a^2 = 9, b^2 = 16 \]
Step 2: Compute \(c\). \[ c^2 = 9 + 16 = 25 \] \[ c = 5 \]
Step 3: Write focus. \[ (\pm 5, 0) \]
Step 1: Identify values. \[ a^2 = 9, b^2 = 16 \]
Step 2: Compute \(c\). \[ c^2 = 9 + 16 = 25 \] \[ c = 5 \]
Step 3: Write focus. \[ (\pm 5, 0) \]
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