Question:
One mole of an alkene reacts with acidic $KMnO_{4}$ to give two moles of ethanoic acid. What is the alkene?
One mole of an alkene reacts with acidic $KMnO_{4}$ to give two moles of ethanoic acid. What is the alkene?
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Terminal alkenes ($R-CH=CH_2$) yield $CO_2$ and a carboxylic acid under these conditions.
Updated On: Apr 28, 2026
- 2-Methylpropene
- 1-Butene
- 2-Pentene
- 2-Butene
- 2-Methyl-2-butene
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Acidic $KMnO_4$ causes oxidative cleavage of the double bond.
Step 2: Meaning
Symmetrical alkenes cleavage results in two identical carboxylic acid molecules.
Step 3: Analysis
Ethanoic acid is $CH_3COOH$ (2 carbons). Two moles imply a 4-carbon symmetrical alkene. $CH_3-CH=CH-CH_3$ (2-Butene) cleaves to form $2 \times CH_3COOH$.
Step 4: Conclusion
The alkene is 2-Butene. Final Answer: (D)
Acidic $KMnO_4$ causes oxidative cleavage of the double bond.
Step 2: Meaning
Symmetrical alkenes cleavage results in two identical carboxylic acid molecules.
Step 3: Analysis
Ethanoic acid is $CH_3COOH$ (2 carbons). Two moles imply a 4-carbon symmetrical alkene. $CH_3-CH=CH-CH_3$ (2-Butene) cleaves to form $2 \times CH_3COOH$.
Step 4: Conclusion
The alkene is 2-Butene. Final Answer: (D)
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