One mapping is selected at random from all mappings of the set S=1,2,3,…,n into itself.
The probability that it is one–one is (3)/(32). Then the value of n is
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Probability of a one–one mapping on an n-set is (n!)/(nⁿ).
Step 1: Total mappings from a set of n elements into itself:
nⁿ
Step 2: Number of one–one mappings (permutations):
n!
Step 3: Given probability:
(n!)/(nⁿ)=(3)/(32)
Step 4: Checking values:
n=4 ⟹ (4!)/(4⁴)=(24)/(256)=(3)/(32)
Hence, n=4.