Question:
One end of a capillary tube is dipped in water, the rise of water column is '\(h\)'. The upward force of 98 dyne due to surface tension is balanced by the force due to the weight of the water column. The inner circumference of the capillary is ( surface tension of water \(= 7 \times 10^{-2}\text{Nm}^{-1}\) )
One end of a capillary tube is dipped in water, the rise of water column is '\(h\)'. The upward force of 98 dyne due to surface tension is balanced by the force due to the weight of the water column. The inner circumference of the capillary is ( surface tension of water \(= 7 \times 10^{-2}\text{Nm}^{-1}\) )
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Always convert dyne to Newton: \(1\text{ dyne} = 10^{-5}\text{ N}\).
Updated On: Apr 26, 2026
- \(1.4\text{ cm}\)
- \(0.7\text{ cm}\)
- \(0.14\text{ cm}\)
- \(0.07\text{ cm}\)
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The Correct Option is A
Solution and Explanation
Concept:
Surface tension force: \[ F = T \times \text{circumference} \] Step 1: Convert units. \[ 98 \text{ dyne} = 9.8 \times 10^{-4} \text{ N} \]
Step 2: Find circumference. \[ C = \frac{F}{T} = \frac{9.8 \times 10^{-4}}{7 \times 10^{-2}} \] \[ C = 1.4 \times 10^{-2} \text{ m} = 1.4 \text{ cm} \]
Step 3: Conclusion. Circumference = \(1.4\text{ cm}\)
Surface tension force: \[ F = T \times \text{circumference} \] Step 1: Convert units. \[ 98 \text{ dyne} = 9.8 \times 10^{-4} \text{ N} \]
Step 2: Find circumference. \[ C = \frac{F}{T} = \frac{9.8 \times 10^{-4}}{7 \times 10^{-2}} \] \[ C = 1.4 \times 10^{-2} \text{ m} = 1.4 \text{ cm} \]
Step 3: Conclusion. Circumference = \(1.4\text{ cm}\)
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