Question:

On the magnetic meridian at some place of the Earth’s surface the vertical component of Earth’s magnetic field is \(0.433\,G\) and the dip angle is \(60^\circ\). Then the magnetic field of the Earth at this place is:

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Use \(B_V = B \sin I\) and \(B_H = B \cos I\) in Earth magnetism problems.
Updated On: Jun 19, 2026
  • \(0.5\,G\)
  • \(1.4\,G\)
  • \(1.7\,G\)
  • \(0.7\,G\)
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The Correct Option is A

Solution and Explanation

Step 1: Use relation of vertical component.
Vertical component of Earth’s magnetic field is: \[ B_V = B \sin I \] where \(I\) is dip angle.

Step 2: Substitute values.

\[ 0.433 = B \sin 60^\circ \] \[ \sin 60^\circ = \frac{\sqrt{3}}{2} \approx 0.866 \]

Step 3: Solve for \(B\).

\[ B = \frac{0.433}{0.866} = 0.5\,G \]

Step 4: Final conclusion.

Thus, total magnetic field is: \[ \boxed{0.5\,G} \]
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