Question:
On complete combustion $0.12\ \text{g}$ of an organic compound gives $0.11\ \text{g}$ of $CO_{2}$. What is the percentage of carbon in the organic compound?
On complete combustion $0.12\ \text{g}$ of an organic compound gives $0.11\ \text{g}$ of $CO_{2}$. What is the percentage of carbon in the organic compound?
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The ratio $\frac{12}{44}$ represents the mass fraction of carbon in carbon dioxide.
Updated On: Apr 28, 2026
- 15%
- 20%
- 25%
- 17.5%
- 21.5%
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The Correct Option is C
Solution and Explanation
Step 1: Concept
Percentage of carbon = $\frac{12}{44} \times \frac{\text{Mass of } CO_2}{\text{Mass of compound}} \times 100$.
Step 2: Meaning
Calculate the fraction of carbon present in the captured $CO_2$ relative to the original sample weight.
Step 3: Analysis
$\%C = \frac{12}{44} \times \frac{0.11}{0.12} \times 100 = \frac{12}{44} \times \frac{11}{12} \times 100 = \frac{1}{4} \times 100 = 25\%$.
Step 4: Conclusion
The percentage of carbon is 25%. Final Answer: (C)
Percentage of carbon = $\frac{12}{44} \times \frac{\text{Mass of } CO_2}{\text{Mass of compound}} \times 100$.
Step 2: Meaning
Calculate the fraction of carbon present in the captured $CO_2$ relative to the original sample weight.
Step 3: Analysis
$\%C = \frac{12}{44} \times \frac{0.11}{0.12} \times 100 = \frac{12}{44} \times \frac{11}{12} \times 100 = \frac{1}{4} \times 100 = 25\%$.
Step 4: Conclusion
The percentage of carbon is 25%. Final Answer: (C)
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