Question:

On adding any three consecutive even numbers, the summation result would always be divisible by which of the following?

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The sum of any three consecutive even numbers is always divisible by \(6\).
Updated On: Jun 6, 2026
  • \(5\)
  • \(7\)
  • \(6\)
  • \(11\)
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The Correct Option is C

Solution and Explanation

Concept:
Consecutive even numbers differ by \(2\). We can represent any three consecutive even numbers algebraically.

Step 1: Let the three consecutive even numbers be:
\[ 2n,\quad 2n+2,\quad 2n+4 \]

Step 2: Add the three numbers.
\[ S=2n+(2n+2)+(2n+4) \] \[ S=6n+6 \] \[ S=6(n+1) \]

Step 3: Interpret the result.

Since the sum is: \[ 6(n+1) \] it is always divisible by \(6\). \[ \therefore \text{Correct Answer is (C)} \]
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