Step 1: Use Newton's second law.
Let the mass of block A be \( m \), and the mass of block B be \( 2m \). The total force applied is 15 N, and the acceleration of the system is given by:
\[
a = \frac{F}{m_{\text{total}}} = \frac{15}{m + 2m} = \frac{15}{3m} = \frac{5}{m}
\]
Step 2: Calculate the force on block B.
The force on block B is \( F_B = 2m \times a = 2m \times \frac{5}{m} = 10 \, \text{N} \).
Final Answer:
\[
\boxed{10 \, \text{N}}
\]