Question:
Observe the given figure of Morgan's experiment for yellow body and white eyed female Drosophila crossed with brown body and red eyed male Drosophila. What will be the percentage of parental type in \( F_{2} \) generation?
Observe the given figure of Morgan's experiment for yellow body and white eyed female Drosophila crossed with brown body and red eyed male Drosophila. What will be the percentage of parental type in \( F_{2} \) generation?
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Linkage rule: Closer genes → fewer recombinants → more parental types.
Updated On: May 4, 2026
- 1.3%
- 62.8%
- 98.7%
- 37.2%
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The Correct Option is C
Solution and Explanation
Concept:
Morgan’s experiment demonstrated linkage and recombination in Drosophila. Genes located close together on the same chromosome tend to be inherited together.
Step 1: Understand parental and recombinant types.
• Parental types → Same combination as parents
• Recombinant types → New combinations due to crossing over
Step 2: Use recombination frequency. In Morgan’s classic experiment: \[ \text{Recombinant frequency} = 1.3\% \] Thus, \[ \text{Parental percentage} = 100\% - 1.3\% = 98.7\% \]
Step 3: Conclusion. \[ \text{Parental type percentage = 98.7\%} \]
Morgan’s experiment demonstrated linkage and recombination in Drosophila. Genes located close together on the same chromosome tend to be inherited together.
Step 1: Understand parental and recombinant types.
• Parental types → Same combination as parents
• Recombinant types → New combinations due to crossing over
Step 2: Use recombination frequency. In Morgan’s classic experiment: \[ \text{Recombinant frequency} = 1.3\% \] Thus, \[ \text{Parental percentage} = 100\% - 1.3\% = 98.7\% \]
Step 3: Conclusion. \[ \text{Parental type percentage = 98.7\%} \]
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