Question:

Number of acyclic structural isomers of the compound having the molecular formula C\(_4\)H\(_{10}\)O is

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Always split into functional groups first (alcohol + ether).
Updated On: May 2, 2026
  • 4
  • 5
  • 6
  • 7
  • 3
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The Correct Option is D

Solution and Explanation

Concept: Structural isomerism in alcohols and ethers
---

Step 1: Possible functional groups

For C$_4$H$_{10}$O:
• Alcohols (R–OH)
• Ethers (R–O–R) ---

Step 2: Count alcohol isomers


• Butan-1-ol
• Butan-2-ol
• 2-methylpropan-1-ol
• 2-methylpropan-2-ol Total alcohols = 4 ---

Step 3: Count ether isomers


• Methoxypropane (different arrangements)
• Ethoxyethane Total ethers = 3 ---

Step 4: Total isomers

\[ 4 + 3 = 7 \] --- Final Answer: \[ \boxed{7} \]
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