Question:

Negation of the statement : $3 + 6 > 8$ and $2 + 3 < 6$ is

Show Hint

When negating mathematical inequalities, remember that the strict inequality symbol flips completely and gains or loses an equality bar:

• $>$ turns directly into $\le$

• $<$ turns directly into $\ge$
Don't forget to flip the word "and" into "or" at the same time!
Updated On: Jun 12, 2026
  • $3 + 6 \le 8$ or $2 + 3 < 6$
  • $3 + 6 < 8$ or $2 + 3 < 6$
  • $3 + 6 \le 8$ or $2 + 3 \ge 6$
  • $3 + 6 > 8$ or $2 + 3 \ge 6$
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
The problem requires us to find the structural negation of a compound mathematical statement joined by the logical connective "and".

Step 2: Key Formula or Approach:
Let the component simple statements be: $p: 3 + 6 > 8$ $q: 2 + 3 < 6$ The given compound statement can be written symbolically as $p \land q$. According to De Morgan's Laws of logic, the negation of a conjunction is equivalent to the disjunction of the individual negations: $$\sim(p \land q) \equiv \sim p \lor \sim q$$

Step 3: Detailed Explanation:
1. Find the negation of the first statement $p$: $$\sim p: \text{Negation of } (3 + 6 > 8) \text{ is } (3 + 6 \le 8)$$ 2. Find the negation of the second statement $q$: $$\sim q: \text{Negation of } (2 + 3 < 6) \text{ is } (2 + 3 \ge 6)$$ 3. Apply De Morgan's Law by combining the negated components with an "or" ($\lor$) logical operator: $$\sim(p \land q) \equiv (3 + 6 \le 8) \text{ or } (2 + 3 \ge 6)$$

Step 4: Final Answer:
The negation of the statement corresponds to option (C).
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