Question:
Minimize $z=x+y$ subject to $2x+3y \ge 6, x \ge 0, y \ge 0$. The solution is ________.
Minimize $z=x+y$ subject to $2x+3y \ge 6, x \ge 0, y \ge 0$. The solution is ________.
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Test all corner points in the objective function.
Updated On: Jun 26, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Concept
The minimum value occurs at one of the corner points of the feasible region.
Step 2: Meaning
Constraints are $2x + 3y = 6$. Intercepts are $(3, 0)$ and $(0, 2)$.
Step 3: Analysis
At $(3, 0), z = 3+0 = 3$. At $(0, 2), z = 0+2 = 2$.
Step 4: Conclusion
The minimum value is 2. Final Answer: (B)
The minimum value occurs at one of the corner points of the feasible region.
Step 2: Meaning
Constraints are $2x + 3y = 6$. Intercepts are $(3, 0)$ and $(0, 2)$.
Step 3: Analysis
At $(3, 0), z = 3+0 = 3$. At $(0, 2), z = 0+2 = 2$.
Step 4: Conclusion
The minimum value is 2. Final Answer: (B)
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