Question:
Mg\(_3\)N\(_2\) reacts with water to produce
Mg\(_3\)N\(_2\) reacts with water to produce
Show Hint
Magnesium nitride reacts with water to produce magnesium hydroxide and ammonia gas.
Updated On: Feb 9, 2026
- Mg(OH)\(_2\) and NH\(_3\)
- Mg(OH)\(_2\) and N\(_2\)O
- MgO and NH\(_3\)
- MgO and NH\(_4\)OH
Hide Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Understanding the reaction.
When magnesium nitride (Mg\(_3\)N\(_2\)) reacts with water, it produces magnesium hydroxide (Mg(OH)\(_2\)) and ammonia gas (NH\(_3\)) as products. The balanced chemical equation is: \[ \text{Mg}_3\text{N}_2 + 6\text{H}_2\text{O} \rightarrow 3\text{Mg(OH)}_2 + 2\text{NH}_3 \] Step 2: Analyzing the options.
(A) Mg(OH)\(_2\) and NH\(_3\): Correct. This is the correct product of the reaction.
(B) Mg(OH)\(_2\) and N\(_2\)O: Incorrect. N\(_2\)O is not produced in this reaction.
(C) MgO and NH\(_3\): Incorrect. Magnesium oxide (MgO) is not a product of this reaction.
(D) MgO and NH\(_4\)OH: Incorrect. Magnesium hydroxide (Mg(OH)\(_2\)) and ammonia (NH\(_3\)) are the correct products.
Step 3: Conclusion.
The correct answer is (A) Mg(OH)\(_2\) and NH\(_3\).
When magnesium nitride (Mg\(_3\)N\(_2\)) reacts with water, it produces magnesium hydroxide (Mg(OH)\(_2\)) and ammonia gas (NH\(_3\)) as products. The balanced chemical equation is: \[ \text{Mg}_3\text{N}_2 + 6\text{H}_2\text{O} \rightarrow 3\text{Mg(OH)}_2 + 2\text{NH}_3 \] Step 2: Analyzing the options.
(A) Mg(OH)\(_2\) and NH\(_3\): Correct. This is the correct product of the reaction.
(B) Mg(OH)\(_2\) and N\(_2\)O: Incorrect. N\(_2\)O is not produced in this reaction.
(C) MgO and NH\(_3\): Incorrect. Magnesium oxide (MgO) is not a product of this reaction.
(D) MgO and NH\(_4\)OH: Incorrect. Magnesium hydroxide (Mg(OH)\(_2\)) and ammonia (NH\(_3\)) are the correct products.
Step 3: Conclusion.
The correct answer is (A) Mg(OH)\(_2\) and NH\(_3\).
Was this answer helpful?
0
0
Top Questions on Chemical Kinetics
- For a reaction : \( N_2 + 3H_2 \rightarrow 2NH_3 \), the rate of reaction with respect to \( NH_3 \) is
- CBSE CLASS XII - 2026
- Chemistry
- Chemical Kinetics
- Following reaction takes place in one step :
\( 2A + B \rightarrow 2C \)
How will the rate of above reaction change if the volume of the reaction vessel is decreased to one third of its original volume? Will there be any change in the order of reaction with the reduced volume?
- CBSE CLASS XII - 2026
- Chemistry
- Chemical Kinetics
- The half-life of a first-order reaction depends on:
- KBPE - 2026
- Chemistry
- Chemical Kinetics
- The initial concentration of the first order reaction:
N2O5 (g) → 2NO2 (g) + 1/2 O2 (g)
was 1.24 × 10⁻² mol L⁻¹ at 300 K. The concentration of N2O5 after 60 minutes was 0.20 × 10⁻² mol L⁻¹.
Calculate the rate constant of the reaction at 300 K.- KBPE - 2026
- Chemistry
- Chemical Kinetics
(i) Write any two differences between order and molecularity.
(ii) What do you mean by pseudo order reaction?- KBPE - 2026
- Chemistry
- Chemical Kinetics
View More Questions
Questions Asked in MHT CET exam
- What is the standard electrode potential of the half-reaction: \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \, (\text{solid})? \] Given that the standard electrode potential for the half-reaction: \[ \text{Ag}^+ + e^- \rightarrow \text{Ag} \, (\text{solid}) \quad \text{is} \, +0.80 \, \text{V}. \] Also, the cell potential for the following reaction is: \[ \text{Cu}^{2+} + 2\text{Ag} \rightarrow \text{Cu} + 2\text{Ag}^+ \] is \( 0.46 \, \text{V} \).
- MHT CET - 2025
- Electrochemistry
- A cylindrical pipe has a radius of \( 0.1 \, \text{m} \). If the speed of water flowing through the pipe is \( 2 \, \text{m/s} \), calculate the volume flow rate of water through the pipe.
- MHT CET - 2025
- mechanical properties of fluid
- A particle is moving with a constant velocity of 5 m/s in a circular path of radius 2 m. What is the centripetal acceleration of the particle?
- MHT CET - 2025
- centripetal acceleration
- A ball is thrown vertically upwards with an initial velocity of 20 m/s. Calculate the time it takes for the ball to reach the highest point. (Assume \( g = 9.8 \, \text{m/s}^2 \))
- MHT CET - 2025
- laws of motion
- A charge of 2 $\mu C$ is placed in an electric field of intensity \( 4 \times 10^3 \, \text{N/C} \). What is the force experienced by the charge?
- MHT CET - 2025
- Electric charges and fields
View More Questions