Question:
Method of preparation of alkyl halide
\(2\text{R-Br}+\text{Hg}_2\text{F}_2\rightarrow 2\text{R-F}+\text{Hg}_2\text{Br}_2\)
This reaction is known as
Method of preparation of alkyl halide
\(2\text{R-Br}+\text{Hg}_2\text{F}_2\rightarrow 2\text{R-F}+\text{Hg}_2\text{Br}_2\)
This reaction is known as
\(2\text{R-Br}+\text{Hg}_2\text{F}_2\rightarrow 2\text{R-F}+\text{Hg}_2\text{Br}_2\)
This reaction is known as
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Heating alkyl bromide or chloride with a metallic fluoride such as AgF or Hg2F2 is the Swarts reaction.
Updated On: Oct 1, 2026
- Finkelstein reaction
- Swartz reaction
- Sandmeyer reaction
- Wurtz reaction
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Alkyl fluorides cannot be made by direct halogenation of alkanes, so they are made by halogen exchange.
Step 2: Detailed Explanation
Swarts reaction: \(\text{R-Br} + \text{AgF}\) (or \(\text{Hg}_2\text{F}_2\), \(\text{CoF}_2\), \(\text{SbF}_3\)) gives \(\text{R-F}\).
Finkelstein reaction makes alkyl iodides with NaI in dry acetone. Sandmeyer reaction converts diazonium salts into aryl halides with CuX. Wurtz reaction couples two alkyl halides with sodium to give alkanes.
Final Answer:
The reaction is the Swarts reaction, option (B). \[ \boxed{\text{Swarts reaction}} \]
Alkyl fluorides cannot be made by direct halogenation of alkanes, so they are made by halogen exchange.
Step 2: Detailed Explanation
Swarts reaction: \(\text{R-Br} + \text{AgF}\) (or \(\text{Hg}_2\text{F}_2\), \(\text{CoF}_2\), \(\text{SbF}_3\)) gives \(\text{R-F}\).
Finkelstein reaction makes alkyl iodides with NaI in dry acetone. Sandmeyer reaction converts diazonium salts into aryl halides with CuX. Wurtz reaction couples two alkyl halides with sodium to give alkanes.
Final Answer:
The reaction is the Swarts reaction, option (B). \[ \boxed{\text{Swarts reaction}} \]
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