Let the number of \(O^{–2}\) ions be \(100\)
and the number of \(Fe^{+2}\) ions be \(X\)
The number of \(Fe^{+3}\) ions be \((93 – X)\)
\(∴ X(2) + (93 – X)3 = 200\)
\(279 – X = 200\)
\(X = 279-200\)
\(X = 79\)
∴ % of \(Fe^{+2}\) ions\(=\frac {79}{93}×100\)
≃ 85%
So, the answer is 85%.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: