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mean effective aperture of a lambda 2 dipole is
Question:
Mean effective aperture of a \(\lambda/2\) dipole is
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Half-wave dipole effective aperture ≈ 0.13 λ².
AP ECET ECE - 2025
AP ECET ECE
Updated On:
Jul 2, 2026
\(0.013\lambda^2\)
\(1.3\lambda^2\)
\(0.13\lambda^2\)
\(13\lambda^2\)
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The Correct Option is
C
Solution and Explanation
Concept:
Effective aperture is related to antenna gain: \[ A_e = \frac{\lambda^2 G}{4\pi} \]
Step 1: Gain of half-wave dipole
\[ G \approx 1.64 \]
Step 2: Substitute
\[ A_e = \frac{\lambda^2 \times 1.64}{4\pi} \]
Step 3: Numerical approximation
\[ 4\pi \approx 12.57 \]
Step 4: Calculation
\[ A_e \approx \frac{1.64}{12.57}\lambda^2 \approx 0.13\lambda^2 \]
Step 5: Conclusion
\[ \boxed{0.13\lambda^2} \]
Final Answer:
\[ \boxed{(C)} \]
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