Question:

Maximum value of \( 2x^3 -15x^2 +36x +4 \)

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Second derivative test identifies maxima/minima.
Updated On: May 1, 2026
  • \( 0 \)
  • \( 3 \)
  • \( 4 \)
  • \( 2 \)
  • \( 5 \)
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The Correct Option is B

Solution and Explanation

Concept: Maxima using derivative.

Step 1:
Differentiate: \[ f'(x)=6x^2-30x+36 \]

Step 2:
Solve: \[ 6(x^2-5x+6)=0 ⇒ x=2,3 \]

Step 3:
Second derivative: \[ f''(x)=12x-30 \]

Step 4:
Check: \[ f''(2)<0 ⇒ max \]

Step 5:
Value: \[ f(2)=? \]
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