Question

Match the terms in List I with their correct descriptions in List II and choose the correct option.

List I	List II
(A) Splicing	(I) Polyadenylation.
(B) Capping	(II) Express sequences or coding sequences.
(C) Tailing	(III) Removal of introns.
(D) Exons	(IV) Addition of methylated guanosine tri phosphate to 5' end.

• (A) - (I), (B) - (II), (C) - (III), (D) - (IV).
• (A) - (II), (B) - (IV), (C) - (I), (D) - (III).
• (A) - (I), (B) - (II), (C) - (IV), (D) - (III).
• (A) - (III), (B) - (IV), (C) - (I), (D) - (II).

Hint:

Splicing removes introns, capping adds a methylated guanosine at the 5' end, tailing adds adenylate residues and exons are coding sequences.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept
In eukaryotes the primary transcript (hnRNA) is processed by splicing, capping and tailing to form mRNA.

Step 2: Matching the terms
Splicing \(\rightarrow\) removal of introns (III).
Capping \(\rightarrow\) addition of methylated guanosine triphosphate to the 5' end (IV).

Step 3: Matching the rest
Tailing \(\rightarrow\) addition of adenylate residues at the 3' end, polyadenylation (I).
Exons \(\rightarrow\) expressed or coding sequences (II).

Step 4: Compare the options
The combination (A)-(III), (B)-(IV), (C)-(I), (D)-(II) is the last option.

Final Answer:
The correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II). \[ \boxed{\text{(D) }\text{(A) - (III), (B) - (IV), (C) - (I), (D) - (II)}} \]