Step 1 : Concept:
This question tests topological classification of subsets of $\mathbb{R}$ under the standard topology (open, closed, clopen, neither).
Step 2 : Key Formulas and Approach:
1. Clopen sets in $\mathbb{R}$ are $\emptyset$ and $\mathbb{R}$.
2. Finite sets contain all their limit points (since they have no limit points), hence closed.
3. Intervals $(a,b)$, $(a,\infty)$, $(-\infty,b)$ are open sets.
4. Dense sets with dense complements in $\mathbb{R}$ (like $\mathbb{Q}$) are neither open nor closed.
Step 3 : Step-by-step Explanation:
• Item A:
The empty set $\emptyset$ is vacuously open and its complement $\mathbb{R}$ is open, so $\emptyset$ is both open and closed (clopen) in $\mathbb{R}$. Matches with III.
• Item B:
Every finite set $S = \{x_1, \dots, x_k\}$ has no limit points ($S' = \emptyset \subseteq S$), so it contains all its limit points and is closed in $\mathbb{R}$. Matches with I.
• Item C:
The set $(0, \infty)$ is an open interval/ray in $\mathbb{R}$, so it is open in $\mathbb{R}$. Matches with IV.
• Item D:
For the set of rational numbers $\mathbb{Q}$:
- $\mathbb{Q}$ contains no open intervals, so it is not open.
- The closure $\overline{\mathbb{Q}} = \mathbb{R} \neq \mathbb{Q}$, so it is not closed.
Thus, $\mathbb{Q}$ is neither open nor closed in $\mathbb{R}$. Matches with II.
Step 4 : Final Answer:
The correct matching is A-III, B-I, C-IV, D-II, which corresponds to option (B).