Question:

Match the LIST-I with LIST-II.

LIST-ILIST-II
A. Mole concept
B. Percentage yield
C. Limiting reagent
D. Avogadro's number
I. \(6.023 \times 10^{23}\)
II. Reactant completely consumed first
III. Ratio of actual yield to theoretical yield
IV. Relate mass to number of particles

Choose the correct answer from the options given below:

Show Hint

Important chemistry facts:
• \(1\) mole \(= 6.023\times10^{23}\) particles
• Limiting reagent gets consumed first
• Percentage yield compares actual and theoretical yield
Updated On: May 22, 2026
  • A-IV, B-III, C-II, D-I
  • A-III, B-IV, C-II, D-I
  • A-I, B-IV, C-III, D-II
  • A-II, B-III, C-IV, D-I
Show Solution
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The Correct Option is A

Solution and Explanation

Concept: The mole concept is one of the most fundamental ideas in chemistry. It helps us relate:
• Mass
• Number of particles
• Volume
• Chemical reactions

Step 1:
Match Mole Concept. The mole concept helps relate: \[ \boxed{ \text{Mass} \leftrightarrow \text{Number of particles} } \] This allows conversion between:
• grams
• atoms
• molecules
• moles Thus: \[ A \rightarrow IV \]

Step 2:
Match Percentage Yield. Percentage yield compares actual yield with theoretical yield. Formula: :contentReference[oaicite:1]{index=1} Hence: \[ \boxed{ \text{Percentage yield} \rightarrow \text{Ratio of actual yield to theoretical yield} } \] Therefore: \[ B \rightarrow III \]

Step 3:
Match Limiting Reagent. Limiting reagent is: “The reactant that gets completely consumed first during a chemical reaction.” Once it is exhausted:
• Reaction stops.
• Product formation stops. Hence: \[ \boxed{ \text{Limiting reagent} \rightarrow \text{Reactant completely consumed first} } \] Thus: \[ C \rightarrow II \]

Step 4:
Match Avogadro's Number. Avogadro's number is: :contentReference[oaicite:2]{index=2} It represents: \[ \boxed{ \text{Number of particles in one mole} } \] Thus: \[ D \rightarrow I \]

Step 5:
Write the final matching. Therefore: \[ \boxed{ A-IV,\ B-III,\ C-II,\ D-I } \]

Step 6:
Match with the options. The correct option is: \[ \boxed{(1)} \] Additional Understanding: Some important formulas: Number of moles: \[ n=\frac{\text{Mass}}{\text{Molar Mass}} \] Number of particles: \[ N=nN_A \] These formulas form the foundation of stoichiometry. Final Conclusion: Correct matching: \[ \boxed{ A-IV,\ B-III,\ C-II,\ D-I } \] Hence, the correct answer is: \[ \boxed{(1)} \]
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