Step 1: Magnetic induction ($B$).
Magnetic induction is force per unit current per unit length. Its dimensional formula is:
\[ [ B ] = ML^{0}T^{-2}A^{-1} \] Hence, A $\rightarrow$ III.
Step 2: Magnetic flux ($\Phi$).
Magnetic flux is given by $B \times \text{area}$.
\[ [ \Phi ] = (ML^{0}T^{-2}A^{-1}) \times L^2 = ML^{2}T^{-2}A^{-1} \] Hence, B $\rightarrow$ IV.
Step 3: Magnetic permeability ($\mu$).
From $B = \mu H$,
\[ [\mu] = \dfrac{[B]}{[H]} = \dfrac{ML^{0}T^{-2}A^{-1}}{A\,L^{-1}} = MLT^{-2}A^{-2} \] Hence, C $\rightarrow$ I.
Step 4: Self inductance ($L$).
Self inductance is flux per unit current.
\[ [L] = \dfrac{ML^{2}T^{-2}A^{-1}}{A} = ML^{2}T^{-2}A^{-2} \] Hence, D $\rightarrow$ II.
Step 5: Final conclusion.
The correct matching is A-III, B-IV, C-I, D-II, corresponding to option (4).