We need to find the dimensional formula of angular impulse.
Angular impulse is defined as the product of torque and time. Torque is the rotational analogue of force, given by \( \vec{\tau} = \vec{r} \times \vec{F} \). The dimensional formula can be derived from this relationship.
Step 1: Write the definition of angular impulse.
\[ \text{Angular Impulse} = \text{Torque} \times \text{Time} \]Step 2: Find the dimensional formula of torque.
Torque (\( \tau \)) = Force × Perpendicular Distance
\[ [\text{Torque}] = [\text{Force}] \times [\text{Distance}] \]The dimensional formula of force is \( [M L T^{-2}] \), and distance is \( [L] \).
\[ [\text{Torque}] = [M L T^{-2}] \times [L] = [M L^2 T^{-2}] \]Step 3: Find the dimensional formula of time.
\[ [\text{Time}] = [T] \]Step 4: Combine the dimensions to get the dimensional formula for angular impulse.
\[ [\text{Angular Impulse}] = [\text{Torque}] \times [\text{Time}] = [M L^2 T^{-2}] \times [T] = [M L^2 T^{-1}] \]Thus, the dimensional formula of angular impulse is [M L² T⁻¹].
Match the LIST-I with LIST-II: 
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Match the LIST-I with LIST-II 
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Two positively charged particles \(m_1\) and \(m_2\) have been accelerated across the same potential difference of 200 keV. Given mass of \(m_1 = 1 \,\text{amu}\) and \(m_2 = 4 \,\text{amu}\). The de Broglie wavelength of \(m_1\) will be \(x\) times that of \(m_2\). The value of \(x\) is _______ (nearest integer). 