Question

Match the LIST-I with LIST-II

• A. A-III, B-IV, C-I, D-II
• B. A-I, B-III, C-IV, D-II
• C. A-IV, B-III, C-I, D-II
• D. A-II, B-I, C-III, D-IV

Hint:

Genetic Disease Mechanisms:
Burkitt's Lymphoma = Reciprocal Translocation $t(8;14)$.
Charcot-Marie-Tooth 1A = Segmental Duplication ($PMP22$).
Color Blindness = Monogenic X-linked disorder.
Turner Syndrome = Monosomy X ($45, X$).

Answer 1

The Correct Option is C

Step 1: Understanding the Question:
The question requires matching structural chromosome alterations or genetic disorder classifications in LIST-I with specific disease examples in LIST-II.

Step 2: Key Formula or Approach:
Match genetic terms with disease etiology:
• Translocation: Reciprocal chromosomal exchange $\to$ Burkitt's Lymphoma $t(8;14)$.

• Monogenic Disorder: Single gene mutation $\to$ Color blindness (X-linked gene mutation).

• Duplication: Segmental gene duplication $\to$ Charcot-Marie-Tooth disease type 1A (PMP22 gene duplication).

• Turner's Syndrome: Sex chromosome monosomy $\to 45, X$.

Step 3: Detailed Explation:

• A. Translocation $\to$ IV. Burkitt's Lymphoma: Caused by reciprocal translocation $t(8;14)(q24;q32)$, moving the $c-MYC$ proto-oncogene next to the immunoglobulin heavy chain ($IGH$) enhancer.

• B. Monogenic disorder $\to$ III. Color blindness: Red-green color blindness is a classic single-gene (monogenic) X-linked recessive disorder.

• C. Duplication $\to$ I. Charcot-Marie-Tooth: CMT1A is caused by a $1.5\ \text{Mb}$ tandem duplication of the $PMP22$ gene on chromosome $17p11.2$.

• D. Turner's Syndrome $\to$ II. 45, X: A sex chromosome aneuploidy characterized by female monosomy X ($45, X$).

Step 4: Fil Answer:
The correct matching sequence is A-IV, B-III, C-I, D-II.