Question

Match the LIST-I with LIST-II

• A. A-IV, B-II, C-I, D-III
• B. A-IV, B-III, C-I, D-II
• C. A-III, B-IV, C-I, D-II
• D. A-II, B-III, C-I, D-IV

Hint:

Nucleosome Metrics:
Core Nucleosome Particle = $147\ \text{bp}$ D + Core Histone Octamer.
Chromatosome (Core + Linker H1) = $166\ \text{bp}$ D.
Exon = Coding sequence (I), Intron = Non-coding sequence (IV).

Answer 1

The Correct Option is B

Step 1: Understanding the Question:
The question requires matching genomic R elements and chromatin packaging structures in LIST-I with their definitions or D length values in LIST-II.

Step 2: Key Formula or Approach:
Match terms based on molecular biology definitions:
• Intron: Non-coding intervening sequence in pre-mR.

• Exon: Coding expressed sequence retained in mature mR.

• Core Histones Core Nucleosome Particle: 147 base pairs of D wrapped around histone octamer.

• Chromatosome (Core + Linker Histone H1): 166 base pairs of D bound to core octamer plus H1 linker histone.

Step 3: Detailed Explation:

• A. Intron $\to$ IV. Non-coding sequence: Introns are non-coding regions removed during pre-mR splicing.

• B. Core histones $\to$ III. 147 base pairs: The core nucleosome particle consists of $1.65$ turns of double-stranded D ($\sim 147\ \text{bp}$) wrapped around an octamer of core histones ($\text{H2A, H2B, H3, H4}$).

• C. Exon $\to$ I. Coding sequences: Exons represent protein-coding regions that are spliced together to form mature mR.

• D. Linker histone $\to$ II. 166 base pairs: Addition of linker histone H1 locks D onto the nucleosome, forming a chromatosome that protects $\sim 166\ \text{bp}$ of D.

Step 4: Fil Answer:
The correct matching sequence is A-IV, B-III, C-I, D-II.