Question:

Match the LIST-I with LIST-II

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Logic Tip: Cobalt = Blue. Tin = White (Opacifier). Chrome = Green. Iron = Brown/Rust.
Updated On: Jun 4, 2026
  • A-IV, B-II, C-I, D-III
  • A-III, B-II, C-I, D-IV
  • A-II, B-I, C-III, D-IV
  • A-IV, B-I, C-III, D-II
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The Correct Option is D

Solution and Explanation

Concept:
Metallic oxides are the traditional colorants used in ceramic glazes. Each oxide typically produces a signature color depending on the base glaze chemistry and kiln atmosphere.

Step 1:
Cobalt is the strongest colorant in ceramics. Even in tiny amounts (0.5% to 2%), it reliably produces a deep, intense Blue in almost all base glazes. (A-IV)

Step 2:
Chrome ($Cr_2O_3$) is a highly refractory colorant that typically yields a dense, opaque Green. (Note: It can produce pink/red if tin is present, but green is its primary base color). (B-I)

Step 3:
Tin Oxide ($SnO_2$) is not a colorant; it is an opacifier. It does not dissolve in the glaze melt, but rather suspends in the glass, scattering light to turn a clear glaze opaque White. (C-III)

Step 4:
Iron Oxide ($Fe_2O_3$) is the most common earth pigment. In a standard oxidation firing, it produces warm earthy tones ranging from yellow and amber to dark Brown and red-brown. (D-II)

Step 5:
Matching these gives A-IV, B-I, C-III, D-II, which corresponds to Option 4. \[ \boxed{\text{(4) A-IV, B-I, C-III, D-II}} \]
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