Question:
Match Structure with their Common Name:
Match Structure with their Common Name:
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Vinyl chloride = \(CH_2=CHCl\), Allyl chloride = \(CH_2=CHCH_2Cl\), Ethylene dichloride = \(ClCH_2CH_2Cl\), Ethylidene chloride = \(CH_3CHCl_2\).
Updated On: Jun 11, 2026
- (A)-(I), (B)-(IV), (C)-(II), (D)-(III)
- (A)-(I), (B)-(II), (C)-(IV), (D)-(III)
- (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- (A)-(III), (B)-(II), (C)-(IV), (D)-(I)
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The Correct Option is A
Solution and Explanation
Concept:
Several halo compounds are widely known by their common names. Matching the structure with the traditional name is important.
Step 1: Identify compound (A).
\[ H_2C=CHCH_2Cl \] contains an allyl group attached to chlorine. Therefore, \[ (A)\rightarrow(I) \] \[ \boxed{\text{Allyl chloride}} \]
Step 2: Identify compound (B).
\[ CH_3CHCl_2 \] contains two chlorine atoms attached to the same carbon atom. This is called ethylidene chloride. \[ (B)\rightarrow(IV) \]
Step 3: Identify compound (C).
\[ ClCH_2CH_2Cl \] is 1,2-dichloroethane. Its common name is ethylene dichloride. \[ (C)\rightarrow(II) \]
Step 4: Identify compound (D).
\[ H_2C=CHCl \] is chloroethene. Its common name is vinyl chloride. \[ (D)\rightarrow(III) \]
Step 5: Write final matching.
\[ (A)-(I),\ (B)-(IV),\ (C)-(II),\ (D)-(III) \] Hence, \[ \boxed{\text{Option (A)}} \]
Step 1: Identify compound (A).
\[ H_2C=CHCH_2Cl \] contains an allyl group attached to chlorine. Therefore, \[ (A)\rightarrow(I) \] \[ \boxed{\text{Allyl chloride}} \]
Step 2: Identify compound (B).
\[ CH_3CHCl_2 \] contains two chlorine atoms attached to the same carbon atom. This is called ethylidene chloride. \[ (B)\rightarrow(IV) \]
Step 3: Identify compound (C).
\[ ClCH_2CH_2Cl \] is 1,2-dichloroethane. Its common name is ethylene dichloride. \[ (C)\rightarrow(II) \]
Step 4: Identify compound (D).
\[ H_2C=CHCl \] is chloroethene. Its common name is vinyl chloride. \[ (D)\rightarrow(III) \]
Step 5: Write final matching.
\[ (A)-(I),\ (B)-(IV),\ (C)-(II),\ (D)-(III) \] Hence, \[ \boxed{\text{Option (A)}} \]
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