Question

Match List-I with the List-II

List-I Tetrahedral Complex	List-II Electronic configuration
(A) TiCl4	(I) e2, t20
(B) [FeO4]2-	(II) e4, t23
(C) [FeCl4]-	(III) e0, t22
(D) [CoCl4]2-	(IV) e2, t23

Choose the correct answer from the options given below:

• A. (A)-(I), (B)-(III), (C)-(IV), (D)-(II)
• B. (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
• C. (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
• D. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Answer 1

The Correct Option is D

To match the tetrahedral complexes in List-I with their corresponding electronic configurations in List-II, we need to consider the oxidation states of the metal ions and their electronic configurations:

1. Titanium Tetrachloride, TiCl₄:
   • Titanium is in the +4 oxidation state in TiCl₄, resulting in an electron configuration of d⁰.
   • Electronic configuration: e⁰, t₂² (Configuration III matches d⁰ state with unpaired electrons being first placed in e).
2. Ferrate Ion, [FeO₄]^2-:
   • Iron in [FeO₄]^2- typically occurs in the +6 oxidation state, which removes all 3d electrons, giving a vacant orbital.
   • Electronic configuration: e², t₂⁰ (Configuration I is a match considering vacant t₂ orbitals filled e).
3. Tetrachloroferrate(III), [FeCl₄]^-:
   • Iron is in the +3 oxidation state in [FeCl₄]^-, giving a d⁵ electronic configuration.
   • Electronic configuration: e², t₂³ (Configuration IV aligns with high spin d⁵ configuration).
4. Tetrachlorocobaltate(II), [CoCl₄]^2-:
   • Cobalt in the +2 oxidation state in this complex has a d⁷ configuration.
   • Electronic configuration: e⁴, t₂³ (Configuration II matches with high spin d⁷ configuration, distinguishing between paired and unpaired).

Consequently, the correct matching of List-I with List-II is:

• (A) TiCl₄ - (III) e⁰, t₂²
• (B) [FeO₄]^2- - (I) e², t₂⁰
• (C) [FeCl₄]^- - (IV) e², t₂³
• (D) [CoCl₄]^2- - (II) e⁴, t₂³

Thus, the correct answer is: (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Answer 2

Thus the correct answer is Option 4.