According to Molecular Orbital Theory (M.O.T.):
For \( O_2 \):
Number of unpaired electrons = 2
For \( O_2^{1-} \):
Number of unpaired electrons = 1
For NO:
Number of unpaired electrons = 1
For \( CN^- \):
Number of unpaired electrons = 0
For \( O_2^{2-} \):
Number of unpaired electrons = 0
Therefore, the number of species having exactly one unpaired electron is 2 (\( O_2^{1-} \) and NO).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

| List-I Tetrahedral Complex | List-II Electronic configuration |
|---|---|
| (A) TiCl4 | (I) e2, t20 |
| (B) [FeO4]2- | (II) e4, t23 |
| (C) [FeCl4]- | (III) e0, t22 |
| (D) [CoCl4]2- | (IV) e2, t23 |
When the excited electron of a H atom from n = 5 drops to the ground state, the maximum number of emission lines observed are ____.
Outermost electronic configurations of four elements A,B,C,D are given below:
(A) 3s2 (B) s23p1 (C) 3s23p3 (D) 3s23p4
The correct order of fist ionization enthalpy for them is:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)