Question

Match List I with List II

List I Compounds	List II Uses
(A). Chlorine	(I). as a preservative
(B). \(\text{SO}_{2}\)	(II). in a petroleum refining
(C). Sulfuric acid	(III). manufacturing of steel
(D). Oxygen	(IV). extraction of gold and platinum metal

Choose the correct answer from the options given below:

• (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
• (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
• (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
• (A) - (III), (B) - (IV), (C) - (I), (D) - (II)

Hint:

Recall one main industrial use of each substance and match the four pairs together.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
Each substance has a well known use. Match them one by one and then pick the option which fits all four pairs.

Step 2: Matching the uses
Chlorine dissolves gold and platinum as chloro complexes, so (A) goes with (IV).
\(\text{SO}_{2}\) acts as a preservative for squashes and dried fruits, so (B) goes with (I).

Step 3: Matching the rest
Sulfuric acid is used in petroleum refining, so (C) goes with (II).
Oxygen is blown into molten iron to remove carbon and impurities in steel making, so (D) goes with (III).

Step 4: Compare the options
The set (A)-(IV), (B)-(I), (C)-(II), (D)-(III) appears only in option (C).

Final Answer:
The correct matching is (A)-(IV), (B)-(I), (C)-(II), (D)-(III). \[ \boxed{\text{(C) }\text{(A) - (IV), (B) - (I), (C) - (II), (D) - (III)}} \]