Question

Match List - I with List - II.

List - I	List - II
A. NOR gate B. NAND gate C. XOR gate D. XNOR gate	I. High output when both inputs are different II. Low output when any of input is high III. High output when any of input is low IV. High output when both the inputs are same

• A. A-II, B-I, C-III, D-IV
• B. A-II, B-III, C-I, D-IV
• C. A-II, B-III, C-IV, D-I
• D. A-III, B-II, C-I, D-IV

Hint:

Important memory trick:
• XOR \(\rightarrow\) HIGH for different inputs
• XNOR \(\rightarrow\) HIGH for same inputs
• NAND \(\rightarrow\) Opposite of AND
• NOR \(\rightarrow\) Opposite of OR

Answer 1

The Correct Option is B

Concept: Logic gates are the fundamental building blocks of digital electronics. Each gate performs a specific logical operation depending on its truth table. The important gates involved in this question are:
• NOR gate
• NAND gate
• XOR gate
• XNOR gate We match each gate with its correct functionality.

Step 1: Analyze NOR gate. The NOR gate is the complement of OR gate. Its output equation is: :contentReference[oaicite:0]{index=0} Important property:
• Output becomes LOW whenever any input becomes HIGH. Hence: \[ \text{NOR gate} \rightarrow \text{Low output when any input is high} \] Therefore: \[ A \rightarrow II \]

Step 2: Analyze NAND gate. NAND gate is the complement of AND gate. Its equation is: :contentReference[oaicite:1]{index=1} Its output is HIGH except when: \[ A=B=1 \] Therefore:
• If any input is LOW, output becomes HIGH. Hence: \[ \text{NAND gate} \rightarrow \text{High output when any input is low} \] Thus: \[ B \rightarrow III \]

Step 3: Analyze XOR gate. XOR gate gives HIGH output when inputs are different. Its equation is: :contentReference[oaicite:2]{index=2} Truth table observation: \[ 0\oplus1=1 \] \[ 1\oplus0=1 \] Hence: \[ \text{XOR gate} \rightarrow \text{High output when both inputs are different} \] Thus: \[ C \rightarrow I \]

Step 4: Analyze XNOR gate. XNOR is complement of XOR. Its equation is: :contentReference[oaicite:3]{index=3} XNOR output becomes HIGH when: \[ A=B \] Hence: \[ \text{XNOR gate} \rightarrow \text{High output when both inputs are same} \] Therefore: \[ D \rightarrow IV \]

Step 5: Write final matching. Thus the correct matching is: \[ A-II,\ B-III,\ C-I,\ D-IV \]

Step 6: Write final answer. Hence the correct option is: \[ \boxed{(B)\ A-II,\ B-III,\ C-I,\ D-IV} \]