Question

Match List-I with List-II :

List - I(Test/reagent)	List - II(Radical identified)
(A) Lake Test	(I) NO3−
(B) Nessler’s Reagent	(II) Fe3+
(C) Potassium sulphocyanide	(III) Al3+
(D) Brown Ring Test	(IV) NH4+

Identify the correct answer from the options given below :

• A. A-IV, B-II, C-III, D-I
• B. A-II, B-IV, C-III, D-I
• C. A-II, B-III, C-IV, D-I
• D. A-III, B-IV, C-II, D-I

Answer 1

The Correct Option is D

To solve this problem, we need to correctly match the tests or reagents in List-I with the corresponding radicals they identify in List-II.

1. Lake Test: The Lake Test is used to identify the presence of aluminum ions (\text{Al}^{3+}). When an alkaline solution containing aluminum ions is treated, a characteristic blue color is formed, called the "lake". Thus, the correct match is \text{A-III}.
2. Nessler’s Reagent: Nessler’s reagent is used to detect ammonium ions (\text{NH}_4^+). It produces a brown precipitate or color when ammonium ions are present, confirming their presence. Therefore, the correct match is \text{B-IV}.
3. Potassium Sulphocyanide: Potassium sulphocyanide is used to detect ferric ions (\text{Fe}^{3+}). It forms a blood-red complex with ferric ions, indicating their presence. Hence, the correct match is \text{C-II}.
4. Brown Ring Test: The Brown Ring Test is a qualitative analytical procedure used to detect nitrate ions (\text{NO}_3^-\text{)}. The formation of a brown ring at the junction of two layers confirms the presence of nitrate ions. Thus, the appropriate match is \text{D-I}.

With these matches, the correct answer is: A-III, B-IV, C-II, D-I.