Match List - I with List - II:
List - I:
- (A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
- (B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
- (C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
- (D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).
List - II:
- (I) \( \frac{\sigma}{\epsilon_0} \)
- (II) \( \frac{\sigma}{2\epsilon_0} \)
- (III) 0
- (IV) \( \frac{\sigma}{\epsilon_0 r^2} \)
Choose the correct answer from the options given below:
- (A) Electric field inside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
- (B) Electric field at distance \( r > 0 \) from a uniformly charged infinite plane sheet with surface charge density \( \sigma \).
- (C) Electric field outside (distance \( r > 0 \) from center) of a uniformly charged spherical shell with surface charge density \( \sigma \), and radius \( R \).
- (D) Electric field between two oppositely charged infinite plane parallel sheets with uniform surface charge density \( \sigma \).
- (I) \( \frac{\sigma}{\epsilon_0} \)
- (II) \( \frac{\sigma}{2\epsilon_0} \)
- (III) 0
- (IV) \( \frac{\sigma}{\epsilon_0 r^2} \)
Show Hint
- \( {(A)-(IV)}, {(B)-(II)}, {(C)-(III)}, {(D)-(I)} \)
- \( {(A)-(IV)}, {(B)-(I)}, {(C)-(III)}, {(D)-(II)} \)
- \( {(A)-(III)}, {(B)-(II)}, {(C)-(IV)}, {(D)-(I)} \)
- \( {(A)-(I)}, {(B)-(II)}, {(C)-(IV)}, {(D)-(III)} \)
The Correct Option is A
Solution and Explanation
- The electric field inside a uniformly charged spherical shell is 0 (Coulomb’s Law), hence \( {(A)-(III)} \).
- The electric field due to a uniformly charged infinite plane sheet is \( \frac{\sigma}{2\epsilon_0} \), hence \( {(B)-(II)} \).
- The electric field outside a uniformly charged spherical shell behaves like that of a point charge and is \( \frac{\sigma}{\epsilon_0 r^2} \), hence \( {(C)-(IV)} \).
- The electric field between two oppositely charged infinite plane sheets is \( \frac{\sigma}{\epsilon_0} \), hence \( {(D)-(I)} \). Thus, the correct answer is \( {(1)} \).
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