Question

Match the following:

List - I (Taal)	List - II (Number of Divisions / Khands)
A. Pancham Savari	I. 03
B. Aada Chautaal	II. 05
C. Pashto	III. 04
D. Sooltaal	IV. 07

• A. A-I, B-III, C-II, D-IV
• B. A-II, B-III, C-I, D-IV
• C. A-III, B-IV, C-I, D-II
• D. A-IV, B-I, C-III, D-II

Hint:

To remember this layout, remember that Aada Chautaal has a division on every single pairs of beats, which divides its 14 matras into a maximum count of 7 divisions, while the 7-beat Pashto is simply broken down into 3 divisions.

Answer 1

The Correct Option is C

Concept: In Indian classical music, every Taal is a cyclic rhythm pattern measured in terms of beats (Matras). This full cycle (Aavartan) is systematically split into smaller sub-sections or structural compartments known as Vibhags or Khands (divisions). Each division is designated by either a clap (Taali) or a wave of the hand (Khali). To establish the correct match, we examine the structural partition blueprint of each option. Let us analyze each rhythm cycle in detail:
• Pancham Savari: A highly unique and intricate asymmetric cycle consisting of 15 total Matras. Its classic rhythmic partition structure is divided into 4 parts as $3 + 4 + 4 + 4$.
• Aada Chautaal: A popular light and classical cycle consisting of 14 total Matras. Its partition blueprint divides it symmetrically into 7 parts of 2 beats each as $2 + 2 + 2 + 2 + 2 + 2 + 2$.
• Pashto: A brisk, lively cycle consisting of 7 total Matras, heavily featured in gazals and folk genres. Its structural partition blueprint consists of 3 divisions grouped as $3 + 2 + 2$.
• Sooltaal: A classical fast-tempo cycle consisting of 10 total Matras, traditionally used in Dhrupad-style accompaniment. It is symmetrically broken down into 5 uniform divisions as $2 + 2 + 2 + 2 + 2$.

Step 1: Isolate the specific compartment count for each individual item.
By counting the structural groupings calculated above, we get:
• A. Pancham Savari $\rightarrow$ Contains exactly 4 divisions. Hence, $\text{A} \rightarrow \text{III}$.
• B. Aada Chautaal $\rightarrow$ Contains exactly 7 divisions. Hence, $\text{B} \rightarrow \text{IV}$.
• C. Pashto $\rightarrow$ Contains exactly 3 divisions. Hence, $\text{C} \rightarrow \text{I}$.
• D. Sooltaal $\rightarrow$ Contains exactly 5 divisions. Hence, $\text{D} \rightarrow \text{II}$. Compiling these targeted pairs creates the clean sequential match vector: A-III, B-IV, C-I, D-II. This corresponds to option (C).